on numToHex(n, res)
-- Round the input value to the nearest whole-number. (Just in case it's fractional.)
set n to n div 0.5 - n div 1
script o
property hexDigits : missing value
property hexOut : {}
end script
if (n > -1) then
-- The number's positive.
set o's hexDigits to {"0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "A", "B", "C", "D", "E", "F"}
-- Construct a list of the hexadecimal digits, working backwards from the lowest-order one.
set widthNow to 0
repeat
set beginning of o's hexOut to item (n mod 16 + 1) of o's hexDigits
set n to n div 16
set widthNow to widthNow + 1
-- Finish when n is exhausted and the digit count is a multiple of the resolution.
if (n is 0) and (widthNow mod res is 0) then exit repeat
end repeat
else
-- The number's negative.
set o's hexDigits to {"1", "2", "3", "4", "5", "6", "7", "8", "9", "A", "B", "C", "D", "E", "F", "0"}
set negatives to "89ABCDEF"
-- Construct a list of the hexadecimal digits, working backwards from the lowest-order one.
set widthNow to 0
repeat
set c to item (n mod 16 - 1) of o's hexDigits
set beginning of o's hexOut to c
set n to (n + 1) div 16 - 1
set widthNow to widthNow + 1
-- Finish when n is exhausted, the digit count is a multiple of the resolution,
-- and the first digit in the list expresses the negative sign bit.
if (n is -1) and (widthNow mod res is 0) and (c is in negatives) then exit repeat
end repeat
end if
-- Coerce the digit list to string.
set astid to AppleScript's text item delimiters
set AppleScript's text item delimiters to ""
set hexOut to o's hexOut as string
set AppleScript's text item delimiters to astid
return hexOut
end numToHex